Question
Factorise the expressions and divide them as directed:
$(9x^2- 4) ÷ (3x + 2)$
$(9x^2- 4) ÷ (3x + 2)$
✓
Answer
$(9x^2- 4) ÷ (3x + 2)$
We have,$=\frac{9\text{x}^2-4}{3\text{x}+2}$
$=\frac{(3\text{x})^2-(2)^2}{3\text{x}+2}$
$=\frac{(3\text{x}+2)(3\text{x}-2)}{3\text{x}+2} [\therefore\text{a}^2-\text{b}^2=(\text{a}+\text{b})(\text{a}-\text{b})]$
$=3\text{x}-2$
We have,$=\frac{9\text{x}^2-4}{3\text{x}+2}$
$=\frac{(3\text{x})^2-(2)^2}{3\text{x}+2}$
$=\frac{(3\text{x}+2)(3\text{x}-2)}{3\text{x}+2} [\therefore\text{a}^2-\text{b}^2=(\text{a}+\text{b})(\text{a}-\text{b})]$
$=3\text{x}-2$
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