Question
Factorise the expressions and divide them as directed: $\left(x^3+x^2-132 x\right) \div x(x-11)$

Answer

$\left(x^3+x^2-132 x\right) \div x(x-11)$
$=\frac{\text{x}^3+\text{x}^2-132\text{x}}{\text{x}(\text{x}-11)}$
$=\frac{\text{x}(\text{x}^2+\text{x}-132)}{\text{x}(\text{x}-11)}$
$=\frac{\text{x}^2+12\text{x}-11\text{x}-132}{\text{x}-11}$
$=\frac{\text{x}(\text{x}+12)-11(\text{x}+12)}{\text{x}-11}$
$=\frac{(\text{x}+12)(\text{x}-11))}{\text{x}-11}$
$=\text{x}+12$

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