Question
Factorise the following:
$9 x^2-12 x+3$
$9 x^2-12 x+3$
✓
Answer
$9 x^2-12 x+3=9 x^2-9 x-3 x+3$
$=9 x(x-1)-3(x-1)$
$=(9 x-3)(x-1)$
$=3(3 x-1)(x-1)$
$=9 x(x-1)-3(x-1)$
$=(9 x-3)(x-1)$
$=3(3 x-1)(x-1)$
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