Question
Factorise the following by grouping the terms:$8(2a + b)^2 - 8a -4b$
✓
Answer
$8(2a + b)^2 - 8a - 4b$
$= 8(2a + b)^2 - (8a + 4b)$
$= 8(2a + b)^2 - 4(2a + b)$
$= 4(2a + b)[2(2a + b) - 1]$
$= 4(2a + b)[4a + 2b - 1].$
$= 8(2a + b)^2 - (8a + 4b)$
$= 8(2a + b)^2 - 4(2a + b)$
$= 4(2a + b)[2(2a + b) - 1]$
$= 4(2a + b)[4a + 2b - 1].$
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