Question
Factorise the following by taking out the common factors:$12a^3+ 15a^2b - 21ab^2$

Answer

$12 a^3+15 a^2 b-21 a b^2$
Here, the common factor is $3 a$.
Dividing throughout by $3 a$, we get
$\frac{12 a^3}{3 a}+\frac{15 a^2 b}{3 a}-\frac{21 a b^2}{3 a} $
$=4 a^2+5 a b-7 b^2 $
$\therefore 12 a^3+15 a^2 b-21 a b^2 $
$=3 a\left(4 a^2+5 a b-7 b^2\right) .$

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