Question
Factorise the following by the difference of two squares$:64x^2 - 121y^2$
✓
Answer
$64x^2 - 121y^2$
$= (8x)^2 - (1y)^2$
$= (8x - 11y)(8x + 11y).$
$= (8x)^2 - (1y)^2$
$= (8x - 11y)(8x + 11y).$
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