Question
Factorise the following by the difference of two squares$:(x + y)^2 -1$
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Answer
$(x + y)^2 - 1$
$= (x + y)^2 - (1)^2$
$= (x + y + 1)(x + y - 1).$
$= (x + y)^2 - (1)^2$
$= (x + y + 1)(x + y - 1).$
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