Question
Factorise the following.
$p^2+ 14p + 13$
$p^2+ 14p + 13$
✓
Answer
$p^2+ 14p + 13$
$= p^2+ 13p + p + 13 × 1$
$= p(p + 13) + 1(p + 13)$
$= (p + 13)(p + 1)$
$= p^2+ 13p + p + 13 × 1$
$= p(p + 13) + 1(p + 13)$
$= (p + 13)(p + 1)$
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