Question
Factorise the following, using the identity $a^2+2 a b+b^2=(a+b)^2$
$4 x^2+4 x+1$
$4 x^2+4 x+1$
✓
Answer
$4 x^2+4 x+1$
$ =(2 x)^2+2 \times 2 x \times 1+1^2 $
$ =(2 x+1)^2 $
$ =(2 x+1)(2 x+1)$
$ =(2 x)^2+2 \times 2 x \times 1+1^2 $
$ =(2 x+1)^2 $
$ =(2 x+1)(2 x+1)$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Evaluate: $\Bigg\{\Big(\frac{4}{3}\Big)^{-1}-\Big(\frac{1}{4}\Big)^{-1}\Bigg\}^{-1}$
→Factorise: $(x^2– 2xy +y^2) – z^2$
→Multiply the following: $(p + 6), (q - 7)$
→Evaluate:
$78 × 82$
→$78 × 82$
Factorise:$49 a^2+84 a b+36 b^2 $
→Find the product.
$(x+7y)(7x-y)$
→$(x+7y)(7x-y)$
Find the squares of the following numbers using the identity $(a-b)^2=a^2-2 a b+b^2: 498$
→Find the values of the following. $(5^{-1}\times2^{-1})\div6^{-1}$
→For an experiment in Botany, two different plants, plant $A$ and plant $B$ were grown under similar laboratory conditions. Their heights were measured at the end of each week for $3$ weeks. The results are shown in the graph. How much did Plant $B$ grow from the end of the $2^{nd}$ week to the end of the $3^{rd}$ week?
→Tell what property allows you to compute $\frac{1}{3} \times\left(6 \times \frac{4}{3}\right)$ as $\left(\frac{1}{3} \times 6\right) \times \frac{4}{3}$.
→