Question
Factorise the following, using the identity $a^2- 2ab + b^2= (a - b)^2$.
$4y^2- 12y + 9$

Answer

$4 y^2-12 y+9$
$=(2 y)^2-2 \times 2 y \times 3+3^2$
$=(2 y-3)^2$
$=(2 y-3)(2 y-3)$

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