Question
Factorise the following, using the identity $a^2-2 a b+b^2=(a-b)^2.$
$9\text{y}^2-4\text{xy}+\frac{\text{y}^2}{9}$

Answer

$9\text{y}^2-4\text{xy}+\frac{\text{y}^2}{9}$$=\big(3\text{y}\big)^2-2\times3\text{y}\times\frac{2}{3}\text{x}+\Big(\frac{2}{3}\text{x}\Big)^2$
$=\Big(3\text{y}-\frac{2}{3}\text{x}\Big)^2$
$=\Big(3\text{y}-\frac{2}{3}\text{x}\Big)\Big(3\text{y}-\frac{2}{3}\text{x}\Big)$

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