Question
Factorise the following, using the identity $a^2-2 a b+b^2=(a-b)^2 .$
$a^2 y^2-2 a b y+b^2$
$a^2 y^2-2 a b y+b^2$
✓
Answer
$a^2 y^2-2 a b y+b^2$
$(a y)^2-2 \times a y \times b+b^2$
$(a y-b)^2$
$=(a y-b)(a y-b)$
$(a y)^2-2 \times a y \times b+b^2$
$(a y-b)^2$
$=(a y-b)(a y-b)$
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