Question
Factorise the following using the identity $a^2- b^2= (a + b)(a - b).$
$ 16 x^4-81 $

Answer

$ 16 x^4-81 $
$ =\left(4 x^2\right)^2-9^2=\left(4 x^2+9\right)\left(4 x^2-9\right)$
$=\left(4 x^2+9\right)\left[(2 x)^2-3^2\right] $
$ =\left(4 x^2+9\right)(2 x+3)(2 x-3) $

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