Question
Factorise the following using the identity $a^2- b^2= (a + b)(a - b).$
$ 9 x^2-(3 y+z)^2 $
$ 9 x^2-(3 y+z)^2 $
✓
Answer
$ 9 x^2-(3 y+z)^2 $
$ =9 x^2-(3 y+z)^2 $
$ =(3 x)^2-(3 y+z)^2 $
$ =(3 x+3 y+z)(3 x-3 y-z) $
$ =9 x^2-(3 y+z)^2 $
$ =(3 x)^2-(3 y+z)^2 $
$ =(3 x+3 y+z)(3 x-3 y-z) $
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