Question
Factorise the following using the identity $a^2- b^2= (a + b)(a - b).$
$\text{y}^3-\frac{\text{y}}{9}$

Answer

$\text{y}^3-\frac{\text{y}}{9}$$= \text{y}\Big(\text{y}^2-\frac{1}{9}\Big)$
$=\text{y}\bigg[\text{y}^2-\Big(\frac{1}{3}\Big)^2\bigg]$
$=\text{y}\Big(\text{y}+\frac{1}{3}\Big)\Big(\text{y}-\frac{1}{3}\Big)$

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