Question
Factorise the following:$12(2x - 3y)^2 - 2x + 3y - 1$

Answer

$12(2x - 3y)^2 - 1(2x - 3y) - 1$
$= 12a^2 - a - 1 [$Taking $(2x - 3y) = a]$
$= 12a^2 - 4a + 3a - 1$
$= 4a(3a - 1) + 1(3a - 1)$
$= (3a - 1)(4a + 1)$
$= [3(2x - 3y) - 1][4(2x - 3y) + 1]$
$= (6x - 9y - 1)(8x - 12y + 1).$

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