Question
Factorise the following:$(3a - 2b)^2 +3(3a - 2b) - 10$
✓
Answer
$(3a - 2b)^2 + 3(3a - 2b) - 10$
$= (3a - 2b)^2 + 5(3a - 2b) - 2(3a - 2b) - 10$
$= (3a - 2b)(3a - 2b + 5) - 2(3a - 2b +5)$
$= (3a - 2b + 5)((3a - 2b - 2).$
$= (3a - 2b)^2 + 5(3a - 2b) - 2(3a - 2b) - 10$
$= (3a - 2b)(3a - 2b + 5) - 2(3a - 2b +5)$
$= (3a - 2b + 5)((3a - 2b - 2).$
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