Question
Factorise the following:$y^2 + 3y + 2 + by + 2b$
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Answer
$y^2 + 3y + 2 + by + 2b$
$= y^2 + y + 2y + 2 + by + 2b$
$= y^2 + y + by + 2y + 2 + 2b$
$= y(y + 1 + b) + 2(y + 1 + b)$
$= (y + 1 + b)(y + 2).$
$= y^2 + y + 2y + 2 + by + 2b$
$= y^2 + y + by + 2y + 2 + 2b$
$= y(y + 1 + b) + 2(y + 1 + b)$
$= (y + 1 + b)(y + 2).$
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