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Factorisation — MATHEMATICS STD 9 — Question

ICSE BoardEnglish MediumSTD 9MATHEMATICSFactorisation2 Marks
Question
Factorise using the grouping method $:a^2+ 4b^2- 3a + 6b - 4ab$
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Answer

$a^2+ 4b^2- 3a + 6b - 4ab$
$= a^2+ 4b^2- 4ab - 3a + 6b$
$= a^2+ (2b)^2 - 2 \times a \times (2b) - 3(a - 2b) [As (a - b)^2= a^2- 2ab + b^2]$
$= (a - 2b)^2- 3(a - 2b)$
$= (a - 2b)[(a - 2b)- 3]$
$= (a - 2b)(a - 2b - 3)$

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