Question
Factorise using the grouping method $ :m (x - 3y)^2+ n (3y - x) + 5x - 15y$
✓
Answer
$m (x - 3y)^2+ n (3y - x) + 5x - 15y$
$= m (x - 3y)^2 - n (x - 3y) + 5(x - 3y)$
$[$Taking $(x - 3y)$ common from all the three terms$]$
$= (x - 3y) [m(x - 3y) - n + 5]$
$= (x - 3y)(mx - 3my - n + 5)$
$= m (x - 3y)^2 - n (x - 3y) + 5(x - 3y)$
$[$Taking $(x - 3y)$ common from all the three terms$]$
$= (x - 3y) [m(x - 3y) - n + 5]$
$= (x - 3y)(mx - 3my - n + 5)$
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