Question
Factorise:
$x-64 x^3$
$x-64 x^3$
✓
Answer
$x-64 x^3$
$=x\left(1-64 x^2\right)$
$=x\left[(1)^2-(8 x)^2\right]$
$=x(1+8 x)(1-8 x)\left[\therefore a^2-b^2=(a-b)(a+b)\right]$
$=x\left(1-64 x^2\right)$
$=x\left[(1)^2-(8 x)^2\right]$
$=x(1+8 x)(1-8 x)\left[\therefore a^2-b^2=(a-b)(a+b)\right]$
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