Question
Factorise : $(x^2+ 4y^2- 9z^2)^2- 16x^2y^2$

Answer

$(x^2+ 4y^2- 9z^2)^2- 16x^2y^2= (x^2+ 4y^2- 9z^2)^2 - ( 4xy )^2$
$= ( x^2 + 4y^2 - 9z^2 - 4xy )( x^2 + 4y^2 - 9z^2 + 4xy ) [ \because a^2 - b^2 = ( a + b )( a - b )]$
$= ( x^2 + 4y^2 - 4xy - 9z^2 )( x^2 + 4y^2 + 4xy - 9z^2 )$
$= [( x - 2y )^2 - (3z)^2 ][ ( x + 2y )^2 - (3z)^2]$
$= [( x - 2y ) - 3z ][( x - 2y ) + 3z ][( x + 2y ) - 3z ][( x + 2y ) + 3z ]$
$= [ x - 2y - 3z ][ x - 2y + 3z ][ x + 2y - 3z ][ x + 2y + 3z ]$

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