Question
Factorise:
$x^2+y^2-z^2-2 x y$
$x^2+y^2-z^2-2 x y$
✓
Answer
$x^2+y^2-z^2-2 x y$
$=\left(x^2+y^2-2 x y\right)-z^2$
$=(x-y)^2-z^2$
$=(x-y-z)(x-y+z)$
$=\left(x^2+y^2-2 x y\right)-z^2$
$=(x-y)^2-z^2$
$=(x-y-z)(x-y+z)$
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