Question
Factorise:
$\text{x}^2+7\sqrt{6}+60$
$\text{x}^2+7\sqrt{6}+60$
✓
Answer
$\text{x}^2+7\sqrt{6}+60$
$=\text{x}^2+2\sqrt{6}\text{x}+5\sqrt{6}\text{x}+60$
$=\text{x}(\text{x}+2\sqrt{6})+5\sqrt{6}(\text{x}+2\sqrt{6})$
$=(\text{x}+2\sqrt{6})(\text{x}+5\sqrt{6})$
$=\text{x}^2+2\sqrt{6}\text{x}+5\sqrt{6}\text{x}+60$
$=\text{x}(\text{x}+2\sqrt{6})+5\sqrt{6}(\text{x}+2\sqrt{6})$
$=(\text{x}+2\sqrt{6})(\text{x}+5\sqrt{6})$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Solve for $\text{x}\Big(\frac{2}{5}\Big)^{2\text{x}-2}=\frac{32}{3125}.$
→In the adjoining figure, ABC and ABD are two triangles on the same base AB. If line segment CD is
bisected by AB at O, show that $\text{ar}(\triangle\text{ABC})=\text{ar}(\triangle\text{ABD}).$
→bisected by AB at O, show that $\text{ar}(\triangle\text{ABC})=\text{ar}(\triangle\text{ABD}).$
A line passes through the point (-4, 6) and is parallel to x-axis. Find its equation.
Factorise:
a - b - a2 + b2
a - b - a2 + b2
Factorise:
$7\text{x}^2+2\sqrt{14}\text{x}+2$
→$7\text{x}^2+2\sqrt{14}\text{x}+2$
Show that:
$\frac{\Big(\text{a}+\frac{1}{\text{b}}\Big)^\text{m}\times\Big(\text{a}-\frac{1}{\text{b}}\Big)^\text{n}}{\Big(\text{b}+\frac{1}{\text{a}}\Big)^\text{m}\times\Big(\text{b}-\frac{1}{\text{a}}\Big)^\text{n}}=\Big(\frac{\text{a}}{\text{b}}\Big)^{\text{m}+\text{n}}$
→$\frac{\Big(\text{a}+\frac{1}{\text{b}}\Big)^\text{m}\times\Big(\text{a}-\frac{1}{\text{b}}\Big)^\text{n}}{\Big(\text{b}+\frac{1}{\text{a}}\Big)^\text{m}\times\Big(\text{b}-\frac{1}{\text{a}}\Big)^\text{n}}=\Big(\frac{\text{a}}{\text{b}}\Big)^{\text{m}+\text{n}}$
Factorise:
$\sqrt{3}\text{x}^2-10\text{x}+8\sqrt{3}$
→$\sqrt{3}\text{x}^2-10\text{x}+8\sqrt{3}$
The volume of a cube is 512cm3. Find its surface area.
Simplify:
$\sqrt{72}+\sqrt{800}-\sqrt{18}$
→$\sqrt{72}+\sqrt{800}-\sqrt{18}$
Read the Source/ Text given below and answer these questions:
Roshan decorated one of his bathroom wall with tiles as shown in the picture. He was having tiles of four colours orange, yellow, green and blue. He fitted the tiles in 8 columns and 12 rows. The size of one tile was 1 foot × 1 foot and the area of each tile is 1 foot2. He arranged the tile in such a way that colour of tiles in each row and column were in the pattern: Orange → Yellow → green → Blue → Orange → ..... and so on.
questions:
1. Which colour tile was fitted at the point with coordinate (2, 5)?
2. What is the area of the tiles fitted in the rectangular part OABX?
Roshan decorated one of his bathroom wall with tiles as shown in the picture. He was having tiles of four colours orange, yellow, green and blue. He fitted the tiles in 8 columns and 12 rows. The size of one tile was 1 foot × 1 foot and the area of each tile is 1 foot2. He arranged the tile in such a way that colour of tiles in each row and column were in the pattern: Orange → Yellow → green → Blue → Orange → ..... and so on.
questions:
1. Which colour tile was fitted at the point with coordinate (2, 5)?
2. What is the area of the tiles fitted in the rectangular part OABX?