Question
Factorise:
$x^3+27$
$x^3+27$
✓
Answer
$x^3+27$
$=x^3+3^3$
$=(x+3)\left(x^2-3 x+9\right) \text { Since } a^3+b=(a+b)\left(a^2-a b+b^2\right)$
$=x^3+3^3$
$=(x+3)\left(x^2-3 x+9\right) \text { Since } a^3+b=(a+b)\left(a^2-a b+b^2\right)$
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