Question
Factorise:
$x^3-2 x^2 y+3 x y^2-6 y^3$
$x^3-2 x^2 y+3 x y^2-6 y^3$
✓
Answer
$x^3-2 x^2 y+3 x y^2-6 y^3$
$=x^2(x-2 y)+3 y^2(x-2 y)$
$=(x-2 y)\left(x^2+3 y^2\right)$
$=x^2(x-2 y)+3 y^2(x-2 y)$
$=(x-2 y)\left(x^2+3 y^2\right)$
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