Question
Factorise:
$x^3-5 x^2-x+5$
$x^3-5 x^2-x+5$
✓
Answer
$x^3-5 x^2-x+5$
$=x^2(x-5)-1(x-5)$
$=(x-5)\left(x^2-1\right)\left[\therefore a^2-b^2=(a-b)(a+b)\right]$
$=(x-5)(x+1)(x-1)$
$=x^2(x-5)-1(x-5)$
$=(x-5)\left(x^2-1\right)\left[\therefore a^2-b^2=(a-b)(a+b)\right]$
$=(x-5)(x+1)(x-1)$
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