Question
Factorise:
$x(x+y)^3-3 x^2 y(x+y)$

Answer

$x(x+y)^3-3 x^2 y(x+y)$
$=x(x+y)\left[(x+y)^2-3 x y\right]$
$=x(x+y)\left(x^2+y^2+2 x y-3 x y\right)$
$=x(x+y)\left(x^2+y^2-x y\right)$

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