Question
Factoriseusing the grouping method $:x^2+ y^2+ x + y + 2xy$
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Answer
$x^2+ y^2+ x + y + 2xy$
$= ( x^2+ y^2 + 2xy ) + ( x + y ) [As (x + y)^2= x^2+ 2xy + y^2]$
$= ( x + y )^2+ ( x + y )$
$= ( x + y )( x + y + 1 )$
$= ( x^2+ y^2 + 2xy ) + ( x + y ) [As (x + y)^2= x^2+ 2xy + y^2]$
$= ( x + y )^2+ ( x + y )$
$= ( x + y )( x + y + 1 )$
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