Question
Factorise:$x(x + y)^3 - 3x^2y(x + y)$

Answer

$x(x + y)^3 - 3x^2y(x + y)$
$= x(x + y)[(x + y)^2 - 3xy]$
$= x(x + y)(x^2 + y^2 + 2xy - 3xy)$
$= x(x + y)(x^2 + y^2 - xy)$

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