Question
Factorize:
$2L^2mn - 3Lm^2n + 4Lmn^2$
$2L^2mn - 3Lm^2n + 4Lmn^2$
✓
Answer
The greatest common factor of the term
$2L^2mn - 3Lm^2n$ and $4Lmn^2$ of the expression
$2L^2mn - 3Lm^2n + 4Lmn^2$ is $Lmn.$
Also, we can write $2L^2mn =Lmn.2L, 3Lm^2n = Lmn.4Lmn^2= Lmn.4n$
Therefore, $2L^2mn - 3Lm^2n + 4Lmn^2= (Lmn.2L) - (Lmn.3m) + (Lmn.4n)$
$= Lmn(2L - 3m + 4n)$
$2L^2mn - 3Lm^2n$ and $4Lmn^2$ of the expression
$2L^2mn - 3Lm^2n + 4Lmn^2$ is $Lmn.$
Also, we can write $2L^2mn =Lmn.2L, 3Lm^2n = Lmn.4Lmn^2= Lmn.4n$
Therefore, $2L^2mn - 3Lm^2n + 4Lmn^2= (Lmn.2L) - (Lmn.3m) + (Lmn.4n)$
$= Lmn(2L - 3m + 4n)$
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