Question
Factorize:-
$-4 a^2+4 a b-4 c a$
$-4 a^2+4 a b-4 c a$
✓
Answer
The greatest common factor of the term
$-4 a^2+4 a b$ and $4 c a$ of the expression
$-4 a^2+4 a b-4 c a$
Also, we can write $-4 a^2=(-4 a \cdot a), 4 a b=-4 a \cdot(-b)-4 c a$ and $4 c a=(-4 a \cdot c)$
Therefore, $-4 a^2+4 a b-4 c a=(-4 a \cdot a)+(-4 a \cdot(-b))-(4 a \cdot c)$
$-4 a(a-b)$
$-4 a^2+4 a b$ and $4 c a$ of the expression
$-4 a^2+4 a b-4 c a$
Also, we can write $-4 a^2=(-4 a \cdot a), 4 a b=-4 a \cdot(-b)-4 c a$ and $4 c a=(-4 a \cdot c)$
Therefore, $-4 a^2+4 a b-4 c a=(-4 a \cdot a)+(-4 a \cdot(-b))-(4 a \cdot c)$
$-4 a(a-b)$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Express:
56% as a ratio.
56% as a ratio.
Evaluate:$\Big(1\frac{3}{10}\Big)^3$
→Write down the number of faces of the following figures:
Cuboid.
Cuboid.
Solve:
$75 a^3 b^2-108 a b^4$
→$75 a^3 b^2-108 a b^4$
Verify the following:
$\frac{-8}{7}\times\frac{13}{9}=\frac{13}{9}\times\frac{-8}{7}$
→$\frac{-8}{7}\times\frac{13}{9}=\frac{13}{9}\times\frac{-8}{7}$
Using the method of successive subtraction examine whether or not the following numbers are perfect cubes:
1331
1331
Show that:
$\sqrt[3]{27}\times\sqrt[3]{64}=\sqrt[3]{27\times64}$
→$\sqrt[3]{27}\times\sqrt[3]{64}=\sqrt[3]{27\times64}$
Find the following products:
$ \big(\text{p}^2 + 16\big) \big(\text{p}^2−\frac{1}{4}\big)$
→$ \big(\text{p}^2 + 16\big) \big(\text{p}^2−\frac{1}{4}\big)$
Verify Euler's formula for the following polyhedrons:
Solve:
$x^4-625$
→$x^4-625$