Question
Factorize:
64a3 + 125b3 + 240a2b + 300ab2

Answer

64a3 + 125b3 + 240a2b + 300ab2
= (4a)3 + (5b)3 + 3 × (4a)2 × 5b + 3(4a)(5b)2
= (4a + 5b)3 $\big[\because$ a3 + b3 + 3a2b + 3ab2 = (a + b)3$\big]$
= (4a + 5b)(4a + 5b)(4a + 5b)
$\therefore$ 64a3 + 125b3 + 240a2b + 300ab2
= (4a + 5b)(4a + 5b)(4a + 5b)

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