Question
Factorize:
$6ab - b^2 + 12ac - 2bc$
$6ab - b^2 + 12ac - 2bc$
✓
Answer
$6ab - b^2 + 12ac - 2bc$
Taking b common in $(6ab - b^2)$ and $2c$ in $(12ac - 2bc)$
$= b(6a - b) + 2c (6a - b)$
Taking $(6a - b)$ common in the terms
$= (6a - b)(b + 2c)$
$\therefore$ $6ab - b^2 + 12ac - 2bc$
$ = (6a - b)(b + 2c)$
Taking b common in $(6ab - b^2)$ and $2c$ in $(12ac - 2bc)$
$= b(6a - b) + 2c (6a - b)$
Taking $(6a - b)$ common in the terms
$= (6a - b)(b + 2c)$
$\therefore$ $6ab - b^2 + 12ac - 2bc$
$ = (6a - b)(b + 2c)$
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