Question
Factorize of the following algebraic expression:
$-4(x-2 y)^2+8(x-2 y)$

Answer

$-4(x-2 y)^2+8(x-2 y)$
$= [-4(x - 2y) + 8] (x - 2y)$ [taking $(x 2)$ as the common factor]
$= 4[-(x - 2y) + 2] (x - 2y) [$taking $4$ as the common factor of $[-4(x - 2y) + 8]]$
$= 4(2y - x + 2)(x -2y)$

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