Question
Factorize of the following algebraic expression:
$-4(x-2 y)^2+8(x-2 y)$

Answer

$-4(x-2 y)^2+8(x-2 y)$
$=[-4(x-2 y)+8](x-2 y)$ [taking $(x 2)$ as the common factor]
$=4[-(x-2 y)+2](x-2 y)[$ taking 4 as the common factor of $[-4(x-2 y)+8]]$
$=4(2 y-x+2)(x-2 y)$

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