Question
Factorize of the following algebraic expression:
$6(a+2 b)-4(a+2 b)^2$

Answer

$6(a+2 b)-4(a+2 b)^2$
$= [6 - 4(a + 2b) [$taking $(a + 2b$ as the common factor$]$
$= 2[3 - 2(a + 2b)] [$taking $2$ as the common factor of $[6 - 4(a + 2b)]]$
$= 2(3 - 2a - 4b)(a + 2b)$

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