Question
Factorize of the following algebraic expression:
$6(a+2 b)-4(a+2 b)^2$

Answer

$\quad 6(a+2 b)-4(a+2 b)^2$
$=[6-4(a+2 b)[\text { taking }(a+2 b \text { as the common factor }]$
$=2[3-2(a+2 b)][\text { taking } 2 \text { as the common factor of }[6-4(a+2 b)]]$
$=2(3-2 a-4 b)(a+2 b)$

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