Question
Factorize of the following expressions:
$16(a-b)^3-24(a-b)^2$
$16(a-b)^3-24(a-b)^2$
✓
Answer
$16(a-b)^3-24(a-b)^2$
$=8(a-b)^2[2(a-b)-3]\left[\text { taking } 8(a-b)^2 \text { as the common factor] }\right.$
$=8(a-b)^2(2 a-2 b-3)$
$=8(a-b)^2[2(a-b)-3]\left[\text { taking } 8(a-b)^2 \text { as the common factor] }\right.$
$=8(a-b)^2(2 a-2 b-3)$
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