Question
Factorize of the following expressions:
$Lm ^2- mn ^2- Lm + n ^2$

Answer

$Lm ^2- mn ^2- Lm + n ^2$
$=\left( Lm ^2- Lm \right)+\left( n ^2- mn ^2\right)$
$=\operatorname{Lm}(m-1)+ n ^2(1-m)$
$=L m(m-1)-n^2(m-1)[$ since, $(1-m)=-(m-1)]$
$=\left( Lm - n ^2\right)(m-1)[$ taking $(m-1)$ as the common factor]

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free