Question
Factorize of the following expressions: $x^3-2 x^2 y+3 x y^2-6 y^3 $

Answer

$x^3-2 x^2 y+3 x y^2-6 y^3 $
$ =\left(x^3-2 x^2 y\right)+\left(3 x y^2-6 y^3\right) $
$ =x^2(x-2 y)+3 y^2(x-2 y) $
$ =\left(x^2+3 y^2\right)(x-2 y) [$taking $(x - 2y)$ as the common factor$]$

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