Question
Factorize the following expressions:
64a3 - b3
64a3 - b3
✓
Answer
64a3 - b3
= (4a)3 - b3
= (4a - b)((4a)2 + 4a × b + b2)
$\therefore$ [a3 - b3 = (a - b)(a2 + ab + b2)]
= (4a − b)(16a2 + 4ab + b2)
$\therefore$ 64a3 - b3 = (4a - b)(16a2 + 4ab + b2)
= (4a)3 - b3
= (4a - b)((4a)2 + 4a × b + b2)
$\therefore$ [a3 - b3 = (a - b)(a2 + ab + b2)]
= (4a − b)(16a2 + 4ab + b2)
$\therefore$ 64a3 - b3 = (4a - b)(16a2 + 4ab + b2)
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