Question
Factorize the following expressions:
$64a^3- b^3$
$64a^3- b^3$
✓
Answer
$64a^3- b^3$
$= (4a)^3 - b^3$
$= (4a - b)((4a)^2 + 4a \times b + b^2)$
$\therefore$ $[a^3- b^3 = (a - b)(a^2 + ab + b^2)]$
$= (4a − b)(16a^2 + 4ab + b^2)$
$\therefore$ $64a^3 - b^3 = (4a - b)(16a^2+ 4ab + b^2)$
$= (4a)^3 - b^3$
$= (4a - b)((4a)^2 + 4a \times b + b^2)$
$\therefore$ $[a^3- b^3 = (a - b)(a^2 + ab + b^2)]$
$= (4a − b)(16a^2 + 4ab + b^2)$
$\therefore$ $64a^3 - b^3 = (4a - b)(16a^2+ 4ab + b^2)$
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