Question
Factorize the following expressions:
$8x^2y^3- x^5$

Answer

$8x^2y^3- x^5$
$= x^2((2y)^3 - x^3)$
$= x^2(2y - x)((2y)^2 + 2y \times x + x^2)$
$\big[\therefore$ $x^3 - y^3 = (x - y)(x^2 + xy + y^2)$$\big]$
$= x^2(2y - x)(4y^2 + 2xy + x^2)$
$\therefore$ $8x^2y^3 - x^5 = x^2(2y - x)(4y^2 + 2xy + x^2)$

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