Question
Factorize the following expressions : $9 x^2-\frac{1}{16} y^2$

Answer

$9 x^2-\frac{1}{16} y^2$
Here $a =3 x , b =\frac{1}{4} y$
$
\begin{aligned}
& \therefore(3 x)^2-\left(\frac{1}{4} y\right)^2=\left(3 x+\frac{1}{4} y\right)\left(3 x-\frac{1}{4} y\right) \\
& \ldots\left[\left(a^2-b^2\right)=(a+b)(a-b)\right]
\end{aligned}
$

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