Question
Factorize the following expressions: $a^3 + 3a^2b + 3ab^2 + b^3 - 8$

Answer

$=(a+b)^3-8\left[\therefore a^3+3 a^2 b+3 a b^2+b^3=(a+b) 3\right]$
$=(a+b)^3-23=(a+b-2)\left((a+b)^2+(a+b) \times 2+2^2\right)$
$=(a+b-2)\left(a^2+2 a b+b^2+2 a+2 b+4\right)$
$\therefore a^3+3 a^2 b+3 a b^2+b^3-8$
$=(a+b-2)\left(a^2+2 a b+b^2+2 a+2 b+4\right)$

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