Question
Factorize the following expressions:
$p^3+27$
$p^3+27$
✓
Answer
$p^3+27$
$=p^3+3^3$
$\therefore\left[a^3+b^3=(a+b)\left(a^2-a b+b^2\right)\right]$
$=(p+3)\left(p^2-3 p-9\right)$
$\therefore p^3+27=(p+3)\left(p^2-3 p-9\right)$
$=p^3+3^3$
$\therefore\left[a^3+b^3=(a+b)\left(a^2-a b+b^2\right)\right]$
$=(p+3)\left(p^2-3 p-9\right)$
$\therefore p^3+27=(p+3)\left(p^2-3 p-9\right)$
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