Question
Factorize the using appropriate identity: $4{y^2} - 4y + 1$
We can observe that we can apply the identity ${\left( {x - y} \right)^2} = {x^2} - 2xy + {y^2} \Rightarrow {\left( {2y} \right)^2} - 2 \times 2y \times 1 + {\left( 1 \right)^2} = {\left( {2y - 1} \right)^2}$.
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