Question
Factorize:
x4 + x2y2 + y4

Answer

x4 + x2y2 + y4
Adding x2y2 and subtracting x2y2 to the given equation
= x4 + x2y2 + y4 + x2y2 - x2y2
= x4 + 2x2y+ y4 - x2y2
= (x2)2 + 2 × x2 × y2 + (y2)2 - (xy)2
Using the identity (p + q)2 = p2 + q2 + 2pq
= (x2 + y2)2 - (xy)2
Using the identity p2 - q2 = (p + q)(p - q)
= (x2 + y2 + xy)(x2 + y2 - xy)
$\therefore$ x4 + x2y2 + y4 = (x2 + y+ xy)(x2 + y2 - xy)

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