MCQ
Ferrous sulphate on heating gives
- A$SO_2$ and $SO_3$
- B$SO_2$ only
- ✓$SO_3$ only
- D$H_2S$ only
${S^{2 - }}\, + \,{[Fe{(CN)_5}NO]^{2 - }}\, \to \,\mathop {{{[Fe{{(CN)}_5}NOS]}^{4 - }}}\limits_{violet} $
Thus $S^{2-}$ and $SO_3^{2-}$ can be distinguished by using both the given reagents.
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$A.$ $\left[ Fe ( CN )_6\right]^{3-}$;$B.$ $\left[ FeF _6\right]^{3-}$; $C.$ $\left[ CoF _6\right]^{3-}$; $D.$ $\left[ Cr (\text { oxalate })_3\right]^{3-}$; $E.$ $\left[ Ni ( CO )_4\right]$
Choose the correct answer from the options given below:
$(I)$ $\begin{array}{*{20}{c}}
{C{H_3} - C - {O^ - }} \\
{\,\,\,\,\,\,||\,\,} \\
{\,\,\,\,\,\,O\,\,}
\end{array}$
$(II)$ $CH_3O^-$
$(III)$ ${C_6}{H_5}{O^\Theta }$
$(IV)$ (image)